6y^2+20y-14=0

Solution for 6y^2+20y-14=0 equation:

6y^2+20y-14=0

a = 6; b = 20; c = -14;
Δ = b2-4ac
Δ = 202-4·6·(-14)
Δ = 736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{736}=\sqrt{16*46}=\sqrt{16}*\sqrt{46}=4\sqrt{46}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{46}}{2*6}=\frac{-20-4\sqrt{46}}{12}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{46}}{2*6}=\frac{-20+4\sqrt{46}}{12}
$